Explanation:
The relation between change in internal energy, work and heat is as follows.
[tex]Q = \Delta U + W[/tex]
where, Q = heat absorbed or released by the system
[tex]\Delta U[/tex] = change in internal energy
W = work done by or on the system
It is given that system uses 2,380 J of energy to do work. This means that work is done by the system therefore, the value of work done by the system is negative. Heat added to the system is 12,900 J.
Therefore, calculate change in internal energy as follows.
[tex]\Delta U = Q - W[/tex]
= 12,900 J - (-2,380 J)
= (12,900 + 2,380) J
= 15,280 J
Thus, we can conclude that the change in internal energy of the system is 15,280 J.
