Answer:
884 m
Explanation:
The motion of the baseball is a projectile motion: a uniform motion along the horizontal direction and a uniformly accelerated motion along the vertical direction.
The horizontal range of a projectile (the horizontal distance covered by the object before it reaches the original vertical height) is given by
[tex]d=\frac{u^2 sin 2\theta}{g}[/tex]
where
u is the initial speed
[tex]\theta[/tex] is the angle of launch
g = 9.8 m/s^2 is the acceleration of gravity
For the ball in this problem,
u = 100 m/s
[tex]\theta=30^{\circ}[/tex]
Substituting into the equation, we find the range of the ball:
[tex]d=\frac{(100)^2}{9.8} sin (2\cdot 30)=884 m[/tex]
so, the ball will cover 884 m before reaching the original vertical level.
