Answer:
230.2 m
Explanation:
The centripetal acceleration of the pilot at any point in the circle is given by
[tex]a=\frac{v^2}{r}[/tex]
where
v is the speed
r is the radius of the circle
At the lowest point, the speed of the plane is
v = 95.0 m/s
We know that the maximum acceleration that the pilot can substain is
[tex]a=4.00 g = 4.00(9.8)=39.2 m/s^2[/tex]
Therefore, substituting into the equation, we can find the minimum radius of the circle so that the acceleration does not exceed this value:
[tex]r=\frac{v^2}{a}=\frac{(95.0)^2}{39.2}=230.2 m[/tex]
