Answer:
a) 0.74m/s^2
b) going down
c) 21N
Explanation:
To have a better understanding of this problem is necessary to draw a free body diagram.
Analysing the m1 box:
[tex]-m1g*sin(\theta)+t1=m1*a[/tex]
and for m2:
[tex]-m2*g+t2=m2*a[/tex]
[tex]t2=-m2*a+m2*g[/tex]
the acceleration is negative because we assume is going downward
because the tension is the same we can substitude one formula into the other.
[tex]-m1*g*sin(\theta)-m2*a+m2*g=m1*a[/tex]
[tex]a=\frac{2.3*9.8-3.7*9.8*sin(30)}{6.0}\\a=0.74m/s^2[/tex]
because the acceleration is positive the assumption was right.
The m1 block is going up and the m2 block is going down.
if we take a look of the m2 box:
[tex]-mg+T=-m*a\\T=m(g-a)\\T=2.3(9.8-0.74)\\T=21N[/tex]
