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The instruction booklet for your pressure cooker indicates that its highest setting is 11.9 psi . You know that standard atmospheric pressure is 14.7 psi, so the booklet must mean 11.9 psi above atmospheric pressure. At what temperature in degrees Celsius will your food cook in this pressure cooker set on "high"? Express your answer numerically in degrees Celsius. View Available Hint(s) T2 T 2 T_2 = nothing ∘C

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IthaloAbreu

Answer:

118ºC

Explanation:

For the Clausius-Clapeyron equation, we know that:

[tex]ln\frac{P2}{P1} = -\frac{L}{R} x(\frac{1}{T2} - \frac{1}{T1}  )[/tex]

P1 is the atmospheric pressure, P1 = 14.7 psi

P2 is the pressure of the pressure cooker, P2 = 11.9 + 14.7 = 26.6 psi

L is the spefic latent heat of water, L = 40,700 J/K

R is the gas constant, R = 8.314 J/mol*K

T1 is the boling point of water at atmospheric pressure, T1 = 100ºC = 373 K

And T2 is the temperature of the pressure cooker, so:

ln (26.6/14.7) = -40,700/8.314*(1/T2 - 1/373)

0.5931 = -4895.36*(1/T2 - 0.00268)

(1/T2 - 0.00268) = - 0.000121

1/T2 = 0.002559

T2 = 391 K

T2 = 118ºC

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