Answer:
B.[tex]x^{2} +2x-8[/tex]
Step-by-step explanation:
Here the best method to solve is by substituting the end values of the set in each option , otherwise it will a time consuming problem.
Now substitute x=-4 in all the options
A.[tex]x^{2} -2x-8[/tex]
16+8-8=16>0
so out of option A and C option C is correct.
B.[tex]x^{2} +2x-8[/tex]
16-8-8=0 which means for the values of x>-4 [tex]x^{2} +2x-8[/tex]is less than 0
Now substitute x=2 in all the options
A.[tex]x^{2} -2x-8[/tex]
4-4-8=-8<0 . so option A and C both are incorrect.
B.[tex]x^{2} +2x-8[/tex]
4+4-8=0 which means for the values of x<2 [tex]x^{2} +2x-8[/tex] is less than 0
Therefore the correct option is B
