A high school basketball court measures 84 feet by 50 feet. If a coach has her players sprint diagonally across the court, how far do they run (in feet)?

Respuesta :

Answer:

The players run 97.54 feet in total across the diagonal of the field.

Step-by-step explanation:

The basket ball is in the figure of a rectangle.

The dimensions of the court are 84 feet by 50 feet.

Now, by PYTHAGORAS THEOREM

in a right angled triangle ABC:

[tex](base)^{2}  + (height)^{2}  = (hypotenuse)^{2}[/tex]

Here, the the basket ball field,

length of basket field = the base of the triangle

width of the field = the height of triangle

Diagonal of the triangle = Hypotenuse of the triangle

So, [tex](Width)^{2}  + (height)^{2}  = (Diagonal)^{2}[/tex]

or, [tex](84)^{2}  + (50)^{2}   = (D)^{2}[/tex]

or, [tex](D)^{2}  = 7056 + 2500 = 9556\\or, D = \sqrt{9556} = 97.54[/tex]

Hence, the length of the diagonal is 97.54 feets

So, the players run 97.54 feet in total across the diagonal of the field.