Answer:
The players run 97.54 feet in total across the diagonal of the field.
Step-by-step explanation:
The basket ball is in the figure of a rectangle.
The dimensions of the court are 84 feet by 50 feet.
Now, by PYTHAGORAS THEOREM
in a right angled triangle ABC:
[tex](base)^{2} + (height)^{2} = (hypotenuse)^{2}[/tex]
Here, the the basket ball field,
length of basket field = the base of the triangle
width of the field = the height of triangle
Diagonal of the triangle = Hypotenuse of the triangle
So, [tex](Width)^{2} + (height)^{2} = (Diagonal)^{2}[/tex]
or, [tex](84)^{2} + (50)^{2} = (D)^{2}[/tex]
or, [tex](D)^{2} = 7056 + 2500 = 9556\\or, D = \sqrt{9556} = 97.54[/tex]
Hence, the length of the diagonal is 97.54 feets
So, the players run 97.54 feet in total across the diagonal of the field.