Answer:
[tex]4.32\cdot 10^5 hp[/tex], [tex]3.22\cdot 10^8 W[/tex]
Explanation:
The jet is flying at constant velocity: this means that its acceleration is zero, so the net force acting on the jet is also zero.
Therefore, we can write:
[tex]4F_T - F_d = 0[/tex]
where
[tex]F_T = 322,000 N[/tex] is the thrust force generated by each engine of the jet
[tex]F_d[/tex] is the drag force
Solving for Fd,
[tex]F_d = 4 F_T = 4(322,000)=1.288\cdot 10^6 N[/tex]
The velocity of the jet is
[tex]v=250 m/s[/tex]
So, the rate at which the drag force does work (which is the power) is
[tex]P=F_d v[/tex]
and substituting
[tex]F_d = 1.288\cdot 10^6 N\\v = 250 m/s[/tex]
we find
[tex]P=(1.288\cdot 10^6)(250)=3.22\cdot 10^8 W[/tex]
Converting into horsepower,
[tex]P=\frac{3.22\cdot 10^8}{746}=4.32\cdot 10^5 hp[/tex]
