The stoplight had just changed and a 2100 kg Cadillac had entered the intersection, heading north at 3.2 m/s , when it was struck by a 1100 kg eastbound Volkswagen. The cars stuck together and slid to a halt, leaving skid marks angled 35° north of east. How fast was the Volkswagen going just before the impact?

Respuesta :

Explanation:

It is given that,

Mass of the Cadillac, [tex]m_1=2100\ kg[/tex]

Speed of Cadillac, [tex]v_1=3.2\ m/s[/tex] (towards north)

Mass of Volkswagen, [tex]m_2=1100\ kg[/tex]

The cars stuck together and slid to a halt, leaving skid marks angled 35 degrees north of east.

According to the law of conservation of momentum,

The momentum along x axis, [tex]m_1v_1=(m_1+m_2)\ usin35[/tex]............(1)

The momentum along y axis, [tex]m_2v_2=(m_1+m_2)\ ucos35[/tex]...........(2)

From equation (1) and (2) it is clear that,

[tex]\dfrac{m_1v_1}{m_2v_2}=tan35[/tex]

[tex]v_2=\dfrac{m_1v_1}{m_2\ tan35}[/tex]

[tex]v_2=\dfrac{2100\times 3.2}{1100\times \ tan35}[/tex]

[tex]v_2=8.72\ m/s[/tex]

So, the Volkswagen going just before the impact is 8.72 m/s. Hence, this is the required solution.

The initial speed of the Volkswagen before the collision is 8.73 m/s.

Conservation of momentum

The initial speed of the Volkswagen can be determined by applying the principle of conservation of linear momentum as follows;

Momentum of the system along x - axis, m₁v₁  = (m₁ + m₂)vsinθ  (1)

Momentum of the system along y - axis, m₂v₂  = (m₁ + m₂)vcosθ  (2)

divide equation (1) by (2)

[tex]\frac{m_1v_1}{m_2v_2} = tan\theta\\\\v_2 = \frac{m_1 v_1}{m_2 tan(\theta)} \\\\v_2 = \frac{2100 \times 3.2}{1100 \times tan(35)} \\\\v_2 = 8.73 \ m/s[/tex]

Thus, the initial speed of the Volkswagen before the collision is 8.73 m/s.

Learn more about conservation of momentum here: https://brainly.com/question/7538238