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A simple wheel has the form of a solid cylinder of radius r with a mass m uniformly distributed throughout its volume. The wheel is pivoted on a stationary axle through the axis of the cylinder and rotates about the axle at a constant angular speed. The wheel rotates n full revolutions in a time interval t. What is the kinetic energy K of the rotating wheel? Answer in terms of m, r, n, t, and pi.

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umohduke14

Answer: K = (1/2)(pi)nmr^2/t

Explanation:

K=(1/2)Iw^2

I = moment of inertia= (1/2)mr^2

w = angular speed = 2(pi)n/t

K =(1/2)[(1/2)mr^2]{2(pi)n/t

K = (1/2)(pi)nmr^2/t

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