Answer:
26.5 m/s
Explanation:
The tension in the string provides the centripetal force that keeps the toy in circular motion. So we can write:
[tex]T=m\frac{v^2}{r}[/tex]
where:
T is the tension in the spring
m = 0.50 kg is the mass of the toy
r = 1.0 m is the radius of the circle (the length of the string)
v is the speed of the toy
The maximum tension in the string is
T = 350 N
If we substitute this value into the equation, we find the maximum speed that the mass can have before the string breaks:
[tex]v=\sqrt{\frac{Tr}{m}}=\sqrt{\frac{(350)(1.0)}{0.50}}=26.5 m/s[/tex]
