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An isolated conducting sphere has a 8.2 cm radius. One wire carries a current of 1.0000032 A into it while another wire carries a current of 1.0000000 A out of it. How long in seconds would it take for the sphere to increase in potential by 1500 V? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement

Respuesta :

Answer:

It takes 4.27 ms for the sphere to increase in potential by 1500 V

Explanation:

Step 1: Calculate the charge on the sphere

After t seconds the charge will be:

q = 1.0000032 - 1.0000000 = 0.0000032t

Step 2: Calculate the voltage on this surface

V = k* q /R

with V = 1500 V

with R = the radius of the sphere = 8.2 cm

V = k* (0.000032t)/R

t= (R*V)/0.0000032k

t = (0.082*1500)/0.0000032*9*10^9

t= 0.00427 s = 4.27 ms

It takes 4.27 ms for the sphere to increase in potential by 1500 V