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An object initially traveling at a velocity of 52 m/s experiences an acceleration of 9.8 m/s^2 how much time will it take to come to rest

Respuesta :

Answer:

5.3 seconds

Explanation:

Vx = Vx0 + Ax .T

A= de-acceleration

Vx =0   final at rest velocity

Vx0 = initial velocity

T= time to bring the object to a stop

therefore

0 = 52 m/s - (9.8 m/s^2) . T

-52 m/s/ -9.8 m/sec^2 =T

5.3 seconds= T

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