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A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising the helicopter. An 700-kg helicopter rises from rest to a speed of 11.0 m/s in a time of 3.0 s. During this time it climbs to a height of 9.6 m. What is the average power generated by the lifting force?

Respuesta :

Answer:

[tex]P = 36068.7 Watt[/tex]

Explanation:

As we know that average power is the ratio of total work done and total time interval

so we will have

[tex]Power = \frac{Total \: Work}{time}[/tex]

now we know that

[tex]Work = \frac{1}{2}mv^2 + mgh[/tex]

[tex]W = \frac{1}{2}(700)(11^2) + 700(9.8)(9.6)[/tex]

so we will have

[tex]W = 42350 J + 68856 J[/tex]

[tex]W = 108206 J[/tex]

now power is given as

[tex]P = \frac{108206}{3}[/tex]

[tex]P = 36068.7 Watt[/tex]

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