Answer:
[tex]1.3 \cdot 10^2 N/m[/tex]
Explanation:
We can solve the problem by using Hooke's law:
[tex]F=kx[/tex]
where
F is the force applied to the spring
k is the spring constant
x is the compression/stretching of the spring
For the spring in the problem, we have
F = 28 N
x = 2.2 cm = 0.022 m
Solving for k, we find
[tex]k=\frac{F}{x}=\frac{28}{0.022}=1272 N = 1.3 \cdot 10^2 N/m[/tex]
