Answer:
one real solution
Step-by-step explanation:
Let's recall that for the general quadratic expression: [tex]ax^2+bx+c[/tex], the discriminant is defined as: [tex]b^2-4*a*c[/tex] (which is the expression that appears inside the square root when solving for the solutions of the quadratic equation: [tex]ax^2+bx+c=0[/tex]
In our case, the determinant for [tex]4x^2+4x+1[/tex] can therefore be written as: [tex]4^2-4*(4)*(1)=16-16=0[/tex] therefore this corresponds to only one real solution for the associated equation: [tex]4x^2+4x+1=0[/tex]
