contestada

Titanium metal requires a photon with a minimum energy of 6.94×10^−19J to emit electrons.
(a)-What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect? Express your answer using three significant figures.
(b)- What is the wavelength of this light? Express your answer using three significant figures.

Respuesta :

Answer:

(a) Frequency will be [tex]1.05\times 10^{15}Hz[/tex]

(b) Wavelength will be [tex]2.857\times 10^{-7}m[/tex]

Explanation:

We have given that energy of a photon is [tex]E=6.94\times 10^{-19}j[/tex]

Plank's constant [tex]=6.6\times 10^{-14}js[/tex]

(a) We know that energy of photon is given by

[tex]E=h\nu[/tex]

So [tex]6.94\times 10^{-34}=6.6\times 10^{-34}\times \nu[/tex]

[tex]\nu =1.05\times 10^{15}Hz[/tex]

(b)We know that wavelength of photon is given by

[tex]\lambda =\frac{c}{f}=\frac{3\times 10^8}{1.05\times 10^{15}}=2.857\times 10^{-7}m[/tex]