What is the slope-intercept form of the equation of the line that passes through the points (−3, 2) and (1, 5) ?


y=3/4x+72

y=3/4x−92

y=3/4x+17/4

y=3/4x−74

The answer is C: y= 3/4x+17/4

Respuesta :

Answer:

C

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (1, 5)

m = [tex]\frac{5-2}{1+3}[/tex] = [tex]\frac{3}{4}[/tex], thus

y = [tex]\frac{3}{4}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 3, 2), then

2 = - [tex]\frac{9}{4}[/tex] + c ⇒ c = [tex]\frac{17}{4}[/tex]

y = [tex]\frac{3}{4}[/tex] x + [tex]\frac{17}{4}[/tex] → C