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A car weighing 10.1 kN and traveling at 11.5 m/s without negative lift attempts to round an unbanked curve with a radius of 65.0 m. (a) What magnitude of the frictional force on the tires is required to keep the car on its circular path?

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umohduke14

Answer: a) 2095N

Explanation:

M = w/g = 10100/9.8 = 1.03 x 10^3 kg

Normal force = Gravitational force

Fn = M x g

Friction is

f = m x v^2 / r = 1.03 x 10^3 x (11.5)^2 / 65

F = 2.10 x 10^3 N

N/b to calculate maximum friction force,

Fmax = Us x mg

Fmax = Us x 10100N

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