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Kayla's school is selling tickets to a play. On the first day of ticket sales, the school sold 5 senior citizen tickets and 3 child tickets for a total of $69. The school took in $73 on the second day by selling 1 senior citizen ticket and 8 child tickets. Find the price of a senior citizen ticket and the price of a child ticket

Respuesta :

TaeKwonDoIsDead

Answer:

Senior Citizen Tickets Cost = $9

Child Tickets Cost = $8

Step-by-step explanation:

Let price of senior ticket be "s", and

price of child ticket be "c"

5 senior ticket and 3 child ticket cost 69, so we can write:

[tex]5s+3c=69[/tex]

Also, 1 senior and 8 child tickets cost 73, thus we can write:

[tex]s+8c=73[/tex]

Or

[tex]s=73-8c[/tex]

We can put this into 1st equation and get an equation in terms of "c" and solve for c first:

[tex]5s+3c=69\\5(73-8c)+3c=69\\365-40c+3c=69\\296=37c\\c=8[/tex]

Thus, c = 8

Now,

s = 73 - 8c

s = 73 - 8(8)

s = 73 - 64

s = 9

So,

Senior Citizen Tickets Cost = $9

Child Tickets Cost = $8

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