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A reaction taking place in a container with a piston-cylinder assembly absorbs 4850. J of heat and has a change in the internal energy of 1618.5 j. What is the final volume of the container if the reaction occurs under a constant external pressure of 5.5 atm and the initial volume of the container is 10.5 l?

Respuesta :

Answer:

[tex]V_f = 16.3 Ltr[/tex]

Explanation:

As per first law of thermodynamics we know that

heat absorbed = change in internal energy + Work done

so we have

[tex]Heat = 4850 J[/tex]

[tex]\Delta U = 1618.5 J[/tex]

so work done is given as

[tex]4850 = 1618.5 + W[/tex]

[tex]W = 3231.5 J[/tex]

now we know that at constant pressure the work done is given as

[tex]W = P\Delta V[/tex]

[tex]3231.5 = P(V_f - V_i)[/tex]

[tex]3231.5 = 5.5 \times 1.01 \times 10^5(V_f - 10.5 \times 10^{-3})[/tex]

[tex]V_f = 16.3 \times 10^{-3} m^3[/tex]

or we have

[tex]V_f = 16.3 Ltr[/tex]

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