12,281.6 Joules
In our case;
Mass of water vapor, m = 190.0 g
Change in temperature, Δt = 150°C - 118°C = 32°C
Taking the specific heat capacity of water vapor = 2.02 J/g°C
Therefore;
Amount of heat = 190.0 g × 2.02 J/g°C × 32°C
= 12,281.6 Joules
Hence, the amount of heat needed is 12,281.6 Joules