An atom in its ground state is excited when it absorbs a single photon of light. The atom then relaxes back to the ground state by emitting two photons, the first, a red photon at 700 nm, and the second, an infrared photon at 1750 nm. What is the wavelength of the absorbed photon? 500 nm 1225 nm 700 nm 1950 nm 1750 nm

Respuesta :

Answer: Option (a)  is the correct answer.

Explanation:

The given data is as follows.

         wavelength of red photon ([tex]\lambda_{1}[/tex]) = 700 nm

         wavelength of infrared photon ([tex]\lambda_{2}[/tex]) = 1750 nm

Therefore, calculate the wavelength of absorbed photon as follows.

    [tex]\frac{1}{\lambda_{abs}} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}[/tex]

              = [tex]\frac{1}{700} + \frac{1}{1750}[/tex]

              = [tex]\frac{2450}{1225000}[/tex]

or,            [tex]\lambda_{abs}[/tex] = [tex]\frac{1225000}{2450}[/tex]              

                            = 500 nm

Therefore, we can conclude that the wavelength of the absorbed photon is 500 nm.

Lanuel

The wavelength of the absorbed photon is 500 nanometers.

Given the following data:

  • Wavelength of red photon = 700 nm
  • Wavelength of infrared photon = 1750 nm

To find the wavelength of the absorbed photon:

The energy of a photon is inversely proportional to the wavelength of a photon.

Mathematically, this is given by:

[tex]E[/tex] ∝ [tex]\frac{1}{W}[/tex]

Where:

  • E is the energy.
  • W is the wavelength.

The above formula can be rewritten as follows:

[tex]\frac{1}{W} = \frac{1}{W_1} + \frac{1}{W_2}[/tex]

Substituting the given parameters into the formula, we have;

[tex]\frac{1}{W_\alpha } = \frac{1}{700} + \frac{1}{1750}\\\\\frac{1}{W_\alpha } = \frac{1}{500} \\\\W_\alpha = 500[/tex]

Therefore, the wavelength of the absorbed photon is 500 nanometers.

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