Answer:
[tex]I=0.2205kgm/s[/tex]
Explanation:
On each step the basilisk must provide an upward force that counters its weight, which is equal to W=mg. Since there are 4 steps in a given second, each step is performed every 0.25 seconds, so the impulse that each of the basilisk's steps provides will be [tex]I=F\Delta t=W\Delta t=mg\Delta t=(0.090kg)(9.8m/s^2)(0.25s)=0.2205kgm/s[/tex]