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What is the probability that a sample of 50 male graduates will provide a sample mean within $.50 of the population mean, $21.68? b. What is the probability that a sample of 50 female graduates will provide a sample mean within $.50 of the population mean, $18.80? c. In which of the preceding two cases, part (a) or part (b), do we have a higher probability of obtaining a sample estimate within $.50 of the population mean? Why? d. What is the probability that a sample of 120 female graduates will provide a sample mean more than $.30 below the population mean?

Respuesta :

Answer:

B. .9146

c. Part B

D..0548

Step-by-step explanation:

This is the same for parts A,B, and D just plug in the different numbers.

Z=(x-μ)/σ

B. 2.15/[tex]\sqrt{50}\\[/tex]

  =.2899

[tex]\frac{18.30-18.80}{.2899}[/tex]

   =1.724732667

Look up in your z score table +/- 1.72

You should get +.9573

                           -.0427

So take .9573-.0427= .9146 <-- thats the answer!!

Good Luck Pal!!

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