Answer:
[tex]J_x = 0.324 \times 10^{-3}\ kg/m^2.h[/tex]
Explanation:
given,
thickness of steel furnace = 2 mm
high- pressure surface = 2 Kg/m³
low-pressure surface = 0.2 kg/m³
coefficient for nitrogen in this steel = 1.0 × 10⁻¹⁰ m²/s
[tex]J_x = -D[\dfrac{-(C_h-C_l)}{\chi_0}][/tex]
[tex]J_x = -(1\times 10^{-10})[\dfrac{-(2-0.2)}{2 \times 10^{-3}}]\times 3600 s/h[/tex]
[tex]J_x = 0.324 \times 10^{-3}\ kg/m^2.h[/tex]
the flow of nitrogen through the wall is equal to [tex]J_x = 0.324 \times 10^{-3}\ kg/m^2.h[/tex]