Answer:
Option C.
Step-by-step explanation:
The distance of the car from the stop sign, d , in feet, at time t , in seconds, can be found using the equation
[tex]d=1.1t^2[/tex]
The average rate of change of a function f(x) on [a,b] is
[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]
We need to find the average speed of the car, in feet per second, between t=2 and t=5.
At t=2,
[tex]d=1.1(2)^2=4.4[/tex]
At t=5,
[tex]d=1.1(5)^2=27.5[/tex]
The average speed of the car, in feet per second, between t=2 and t=5 is
[tex]\text{Average speed}=\dfrac{d(5)-d(2)}{5-2}[/tex]
[tex]\text{Average speed}=\dfrac{27.5-4.4}{3}[/tex]
[tex]\text{Average speed}=\dfrac{23.1}{3}[/tex]
[tex]\text{Average speed}=7.7[/tex]
The average speed of the car, in feet per second, between t=2 and t=5 is 7.7 feet per second.
Therefore, the correct option is C.
