Answer:
4.167
4.83871 cm
Explanation:
u = Object distance
v = Image distance = 25 cm
f = Focal length = 6 cm
Angular magnification is given by
[tex]m=\frac{25}{f}\\\Rightarrow m=\frac{25}{6}\\\Rightarrow m=4.167[/tex]
The angular magnification of the lens is 4.167
Lens equation
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{6}=\frac{1}{u}+\frac{1}{-25}\\\Rightarrow \frac{1}{6}+\frac{1}{25}=\frac{1}{u}\\\Rightarrow \frac{1}{u}=\frac{31}{150}\\\Rightarrow u=4.83871\ cm[/tex]
The closest distance by which the object can be examined is 4.83871 cm
