Sorry this took a while but it should be the last option for it to be correct.
The equation of a line passing through the point (1, 1) and perpendicular to the line is 4y + x = 5
Let the equation of the line pass through the point (1, 1).
Given the equation y = 4x -1
Find the slope of the line
Given the standard equation as y = mx + b
Compare with the given equation;
mx = 4x
m = 4
The slope of the line perpendicular to the line is -1/4
Get the equation of the line in point-slope form [tex]y-y_0=m(x-x_0)[/tex] to have:
y - 1 = -1/4(x-1)
4(y-1) = -(x-1)
4y - 4 = -x + 1
4y + x = 1 + 4
4y + x = 5
Hence the equation of a line passing through the point (1, 1) and perpendicular to the line is 4y + x = 5
Laearn more here: https://brainly.com/question/17003809
