Answer:
Option C is the correct answer.
Step-by-step explanation:
The height, h(t), of the ball can be modeled as a function of time, t, by the equation h(t) = -16t² + 40t + 20
When the ball hits the ground, we have h(t) = 0
h(t) = -16t² + 40t + 20 = 0
[tex]t=\frac{-40\pm \sqrt{40^2-4\times (-16)\times 20}}{2\times (-16)}=\frac{-40\pm \sqrt{2880}}{-32}\\\\t=\frac{-40\pm 53.67}{-32}\\\\\texttt{t = 2.93s or t = -0.43s}[/tex]
Negative time is not possible, so time = 2.93 seconds.
Option C is the correct answer.
