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2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6.2 feet. Use the position equation to write a mathematical model for the height of the softball

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lublana

Answer:

[tex]-16t^2+30t+5.8[/tex]

Step-by-step explanation:

We are given that

Initial velocity=30 ft/s

Initial position=[tex]s_0=5.8 ft[/tex]

We have to write a mathematical model for height of the softball by using the position equation

The position equation on Earth's surface is given by

[tex]h(t)=-16t^2+v_0t+s_0[/tex]

Where [tex]v_0=[/tex] Initial velocity

[tex]s_0[/tex]=Initial position

Substitute the values in the equation then, we get

[tex]h(t)=-16t^2+30t+5.8[/tex]

Hence, the mathematical model for height of the softball is given by

[tex]-16t^2+30t+5.8[/tex]

baileyhwangg

Answer:

h(t)=-16t^2+30t+5.8

Step-by-step explanation

You first need to use the equation: h(t)=-16t^2+vt+s

V= the initial velocity in feet/second

T= time in motion

H=height at a given time

S= initial height

Therefore,

V= 30ft (per second)

S=5.8

Which is

h(t)=-16t^2+30t+5.8

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