.
A water tank fills through two pipes. Water flows in
through one pipe at a rate of 25,000 gallons per hour
and in through the other pipe at a rate of 45,000
gallons per hour. Water leaves the system at a rate of
60,000 gallons per hour.
There are 3 of these tanks, and each tank holds
1 million gallons. Each tank is half full. Water is
entering and leaving a tank at the maximum
amounts. Determine the number of hours, x, it will
take to fill all 3 tanks one at a time.​

Respuesta :

Answer:

It will take 150 hours to fill all 3 tanks at a time.

Step-by-step explanation:

Water flows in pipe 1 at a rate of 25,000 gallons per hour.

Other pipe at a rate of 45,000 gallons per hour.

Water leaves the system at a rate of 60,000 gallons per hour.

There are 3 of these tanks and each tank holds 1 million gallons.

Each tank is half full.

So, total capacity of 3 tanks = 3 millions and it is half full.

The water need to be filled = 1.5 millions. At the same time 60,000 gallons of water leaving out.

25,000 x + 45,000 x - 60,000 x = 1.5 millions

70,000x -60,000x = 1500000

10,000x = 1500000

Dividing both sides by 10,000, we get

x = 150 hours

Therefore, it will take 150 hours to fill all 3 tanks at a time.