Answer:
-22.5 m/s
Explanation:
[tex]m_1[/tex] = Mass of squid = 1.5 kg
[tex]m_2[/tex] = Mass of water ejected = 0.14 kg
[tex]v_1[/tex] = Velocity of squid = 0.4 m/s
[tex]v_2[/tex] = Velocity of squid after ejection = 2.5 m/s
v = Velocity of water ejection
In this system the momentum is conserved
[tex]m_1v_1+(m_1-m_2)v_2+m_1v=0\\\Rightarrow 1.5\times 0.4-2.5(1.5-0.14)-1.5v=0\\\Rightarrow v=\frac{-1.5\times 0.4+(1.5-0.14)\times 2.5}{-0.14}\\\Rightarrow v=-20\ m/s[/tex]
The velocity of the water ejection relative to the squid is
-20+(-2.5) = -22.5 m/s
The negative sign indicates the opposite direction to the direction of the squid.
