When a spinner is divided into equal parts, each segment in the spinner has an equal probability. The probability that the outcomes of the 3 spin is even is 8/125
Let the numbers on the spinner be:
[tex]S = \{1,2,3,4,5\}[/tex]
[tex]n(S) = 5[/tex]
The even numbers are:
[tex]E =\{2,4\}[/tex]
[tex]n(E) = 2[/tex]
The probability of 1 even number is:
[tex]P(E) = \frac{n(E)}{n(S)}[/tex]
So, we have:
[tex]P(E) = \frac{2}{5}[/tex]
In three spin, the probability that all outcomes are even is:
[tex]P(Even) = P(E) \times P(E) \times P(E)[/tex]
[tex]P(Even) = \frac{2}{5} \times \frac{2}{5} \times \frac{2}{5}[/tex]
[tex]P(Even) = \frac{8}{125}[/tex]
Hence, the probability that the outcomes of the 3 spin is even is 8/125
Read more about probability at:
https://brainly.com/question/13801541
