Answer:
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
Explanation:
Consider the following equations:
[tex]lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }[/tex]
[tex]lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }[/tex]
Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:
[tex]Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} } }[/tex]
where:
Q_d is the activation energy
D_1 is the diffusivity at T_1
D_2 is the diffusivity at T_2
[tex]Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 } }[/tex]
Q_d=35881 J/mol
So the activation energy is 35881 J/mol.
