Answer:
0.0009
Step-by-step explanation:
[tex]\mu=4[/tex]
[tex]\sigma=0.55[/tex]
n = 8
This is the left tailed test .
The null and alternative hypothesis is ,
[tex]H_0:\mu=4[/tex]
[tex]Ha:\mu <4[/tex]
Test statistic = z=-3.12 from the table.
P(z <-3.12 ) = 0.0009
P-value =0.0009