Answer:
The force required to move the quarterback with linebacker is 1215 N
Explanation:
[tex]\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}[/tex]
[tex]\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}[/tex]
[tex]\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}[/tex]
Using Newton's second law, it is established that F = Ma
Where F is net force acting on the system, a is the acceleration and M is mass of the two object [tex]\left(m_{1}+m_{2}\right)[/tex]
Now consider both [tex]\mathrm{m}_{1} \text { and } \mathrm{m}_{2}[/tex]as a system, so net force acting on the system is [tex]\text { Force }=\left(m_{1}+m_{2}\right) a[/tex]
Substitute the given values in the above formula,
[tex]\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}[/tex]
[tex]\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}[/tex]
Force = 1215 N
1215 N is the force required to move the quarterback with linebacker.
