Respuesta :

cristisp93

16.94 % Zn

Explanation:

First we need the molar weight of the  Zn₃(PO₄)₂:

molar weight of Zn₃(PO₄)₂ = atomic weight of Zn × 3 + atomic weight of P × 2 + atomic weight of O × 4 × 2

molar weight of Zn₃(PO₄)₂ = 65.4 × 3 + 31 × 2 + 16 × 4 × 2 = 386 g/moles

Taking in account weight of 1 mole of Zn₃(PO₄)₂ we devise the following reasoning:

if         386 g of Zn₃(PO₄)₂ contains 65.4 g of Zn

then    100 g of Zn₃(PO₄)₂ contains X g of Zn

X = (100 × 65.4) / 386 = 16.94 % Zn

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samueladesida43

The percentage of zinc in the compound; Zn3(PO4)2 is 50.65%.

HOW TO CALCULATE PERCENTAGE?

The percentage of an element in a compound can be calculated by dividing the mass of that element in the compound by the atomic mass of the compound.

% Zinc = mass of Zn/molar mass of Zn3(PO4)2 × 100

The molar mass of Zn3(PO4)2 = 65(3) + {31 + 64}2 = 190 + 195 = 385g/mol

% Zn = 195/385 × 100

% Zn = 50.65%

Therefore, the percentage of zinc in the compound; Zn3(PO4)2 is 50.65%.

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