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C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)

In the reaction represented above, what is the total number of moles of reactants consumed when 1.00 mole of CO2(g) is produced?

Respuesta :

Diatonic254

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

What about ;

? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 :     3

What about

? (x) :     1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

https://brainly.com/question/13967925

https://brainly.com/question/13969737

#LearnWithBrainly

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