Answer:
446.7 °C
Explanation:
We are given with two volumes and one temperature, we have to find another temperature.
[tex]V1=14.5\ lit\\T1=10.5\ C=273.15+10.5=283.65\ K\\V2= 36.8 \ lit\\T2=?[/tex]
Using Charles-volume temperature law:
This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to kelvin temperature.
Or, [tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
Plugging the given values.
[tex]\frac{14.5}{283.65}= \frac{36.8}{T2}\\T2=\frac{283.65\times36.8}{14.5}\\ T2= 719.88K\\T2= 719.88-273.15\\T2=446.7C[/tex]
Thus the final temperature is 446.7 °C
