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What is the pH of the resulting solution when 500 mL of a 0.10 M solution of sodium acetate (CH3COONa) is combined with 500 mL of a 0.10 M solution of acetic acid (CH3COOH)? (pKa of acetic acid = 4.8) A. 1.0B. 1.3(c) 4.8 (d) 7.0 (e) 8.1

Respuesta :

Answer:

The pH of the buffer solution is 4.8 ( option C)

Explanation:

Step 1: Data given

Volume of the 0.10 M sodium acetate solution = 500 mL = 0.5 L

Volume of the 0.10 M acetic acid solution = 500 mL = 0.5 L

pKa = 4.8

Step 2: Calculate pH

pH = pKa + log [A-]/[HA]

pH = pKa + log [CH3COONa]/[CH3COOH]

pH = 4.8 + log [0.1]/[0.1]

pH = 4.8 + log (1)

pH = 4.8 + 0

pH = 4.8

pH = pKa = 4.8

The pH of the buffer solution is 4.8

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