A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits radiation uniformly in all directions (i.e., over 4π steradians).

Respuesta :

Answer:

Intensity, [tex]I=1.101\ W/m^2[/tex]

Explanation:

Power of the light bulb, P  = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

[tex]I=\dfrac{P}{A}[/tex]

[tex]I=\dfrac{P}{4\pi r^2}[/tex]

[tex]I=\dfrac{40\ W}{4\pi (1.7\ m)^2}[/tex]

[tex]I=1.101\ W/m^2[/tex]

So, the intensity of light is [tex]1.101\ W/m^2[/tex].