Answer: a) Quadratic equation b)[tex]4x^2+36x+80[/tex]
Step-by-step explanation:
Since we have given that
Length of photograph = 8 inches
Width of photograph = 10 inches
It is surrounded by a frame with uniform width 'x'.
So, Length of picture and frame becomes
[tex]x+8+x=2x+8[/tex]
Width of picture and frame becomes
[tex]x+10+x=2x+10[/tex]
So, Area of picture and frame becomes
[tex]Length\times breadth\\\\=(2x+8)(2x+10)\\\\=2x(2x+10)+8(2x+10)\\\\=4x^2+20x+16x+80\\\\=4x^2+36x+80[/tex]
Hence, a) Quadratic equation b)[tex]4x^2+36x+80[/tex]