Answer: Our required probability is 0.0062.
Step-by-step explanation:
Since we have given that
Mean = $600
Standard deviation = $40
[tex]\bar{X}=\$700[/tex]
First we will find the test statistic value:
[tex]z=\dfrac{\bar{X}-\mu}{\sigma}\\\\z=\dfrac{700-600}{40}\\\\z=\dfrac{100}{40}\\\\z=2.5[/tex]
By using the Standard normal table,
So, the probability that the actual costs will exceed the budgeted amount is given by
[tex]P(Z>2.5)=0.0062[/tex]
Hence, our required probability is 0.0062.