To solve this problem it is necessary to apply the concepts related to diffraction through a circular opening.
By definition the angular resolution is given by
[tex]\theta = 1.22\frac{\lambda}{D}[/tex]
Where,
[tex]\lambda = Wavelenght[/tex]
D = Diameter of the lens aperture.
Our values are given as,
[tex]\lambda = 600*10^{-9}m[/tex]
[tex]d = 1.5*10^{-2}m[/tex]
Therefore replacing,
[tex]\theta = 1.22\frac{600*10^{-9}}{1.5*10^{-2}}[/tex]
[tex]\theta = 4.88*10^{-5} rad[/tex]
Therefore the angular separation is [tex]4.88*10^{-5} rad[/tex]
The angular separation is [tex]4.88 \times 10^{-5} \;\rm rad[/tex].
The angular resolution of a telescope is the smallest angle between close objects that can be seen clearly to be separate.
Given that the diameter of the small circular aperture of the telescope is 2.0 cm. The wavelength is 600 nanometers and the other circular aperture of diameter is 1.5 centimeters.
The angular separation is calculated as given below.
[tex]\theta _1 = 1.220 \dfrac {\lambda}{d}[/tex]
Where [tex]\lambda[/tex] is the wavelength and d is the diameter of the lens aperture.
[tex]\theta _1 = 1.220 \times\dfrac {600\times 10^{-9}}{1.5\times 10^{-2}}[/tex]
[tex]\theta _1 = 4.88 \times 10^{-5} \;\rm rad[/tex]
Hence we can conclude that the angular separation is [tex]4.88 \times 10^{-5} \;\rm rad[/tex].
To know more about the angular separation, follow the link given below.
https://brainly.com/question/25181883.
