Answer:
The internal energy of system is 29 joule .
Explanation:
Given as :
The amount of work done = Δ W = 108 joule
The heat energy added to the system is Δ Q = 79 joule
Let The change of internal energy = Δ U
Now ,
The change in internal energy = work done by system - heat energy added to system
I.e Δ U = Δ W - Δ Q
Or, Δ U = 108 joule - 79 joule
∴ Δ U = 29 joule
Hence The internal energy of system is 29 joule . Answer
Answer:
Explanation:
Consider the system on which experiment is done. [tex]108\text{ }J[/tex] of work was done on the closed system. All this work will contribute to rise in Internal Energy.
[tex]79\text{ }J[/tex] of heat energy was added to the system. This heat is also a form of energy added to the system. Hence, it adds to the Internal energy.
[tex]Q=\text{ Heat added to the system }=+79\text{ }J[/tex]
[tex]W=\text{ Work done on the system }=+108\text{ }J[/tex]
[tex]\Delta U=Q+W=108+79=+187\text{ }J[/tex]
∴ Internal Energy increases by 187 J
