Answer:
Probability of picking 2 yellow marbles WITHOUT REPLACEMENT
=[tex] \frac{3}{28}[/tex]
Step-by-step explanation:
Number of green marbles = 2
Number of red marbles = 3
Number of yellow marbles = 3
So, the total number of marbles = 2 + 3 + 3 = 8 marbles
Let E : Event of picking a yellow marble from the bag
Now, Probability of an Event E = [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]
⇒ Here, [tex]P(E) = \frac{3}{8}[/tex]
After picking 1 yellow marble from the bag:
Total marbles left in bag = 8 -1 = 7
Total yellow marbles left in bag = 3 - 1 = 2
Now, the probability of picking the second yellow marble WITHOUT REPLACEMENT = [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}} = \frac{2}{7}[/tex]
So, the Probability of picking 2 yellow marbles WITHOUT REPLACEMENT
= [tex]\frac{3}{8} \times \frac{2}{7} = \frac{6}{56} = \frac{3}{28}[/tex]
