To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.
By definition the torque is defined as
[tex]\tau = F*r[/tex]
Where,
[tex]\tau = Torque[/tex]
F = Force
r = Radius
For our values we have:
[tex]\tau = F*r[/tex]
[tex]\tau = (1.75*10^3)(2.8*10^{-2})[/tex]
[tex]\tau = 49Nm[/tex]
Consequently the calculation of the moment of inertia would then be given by the relationship
[tex]\tau = I\alpha[/tex]
[tex]I=\frac{\tau}{\alpha}[/tex]
Replacing with our values
[tex]I = \frac{49}{150}[/tex]
[tex]I = 0.322Kg.m^2[/tex]
The moment of inertia of the boxer's forearm [tex]0.322Kg.m^2[/tex]
The moment of inertia of the box is 0.322kgm².
This is used to measure how resistant an object is to changes in its rotational motion.
Torque = Force × radius
= 1.75 × 10³ N × 2.8 × 10⁻²m
= 49Nm.
Moment of Inertia I = Torque/ angular acceleration
I = 49/150 = 0.322kgm²
Read more about Inertia here https://brainly.com/question/1140505
