The centripetal acceleration of the rock is [tex]10.7 m/s^2[/tex], towards the centre of the circle
Explanation:
The centripetal acceleration of an object in circular motion is given by the equation:
[tex]a=\frac{v^2}{r}[/tex]
where
v is the speed of the object
r is the radius of the circular path
And the direction of the centripetal acceleration is always toward the centre of the circle.
For the rock in this problem, we have:
r = 1.5 m is the radius of the circle
v = 4 m/s is the speed
Substituting, we find the centripetal acceleration:
[tex]a=\frac{(4)^2}{1.5}=10.7 m/s^2[/tex]
And the direction is towards the centre of the circle.
Learn more about centripetal acceleration:
brainly.com/question/2562955
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