Respuesta :
Answer:
Wavelength, [tex]\lambda=6.81\times 10^{-8}\ m[/tex]
Explanation:
It is given that,
The binding energy of an electron is, [tex]E=1.76\times 10^3\ kJ/mol[/tex]
or
The binding energy of an electron is,
[tex]E=\dfrac{1.76\times 10^3}{6.023\times 10^{23}}\times 10^3\ J[/tex]
[tex]E=2.92\times 10^{-18}\ J[/tex]
Let [tex]\lambda[/tex] is the wavelength of light required to remove an electron from the surface of potassium metal by the photoelectric effect. The energy of an electron is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
[tex]\lambda=\dfrac{hc}{E}[/tex]
[tex]\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{2.92\times 10^{-18}}[/tex]
[tex]\lambda=6.81\times 10^{-8}\ m[/tex]
So, the longest wavelength of light required to remove an electron from the surface of potassium metal is [tex]6.81\times 10^{-8}\ m[/tex]. Hence, this is the required solution.
